Chopping and unchopping preserve the width of a data frame, changing its
length. chop()
makes df
shorter by converting rows within each group
into list-columns. unchop()
makes df
longer by expanding list-columns
so that each element of the list-column gets its own row in the output.
chop()
and unchop()
are building blocks for more complicated functions
(like unnest()
, unnest_longer()
, and unnest_wider()
) and are generally
more suitable for programming than interactive data analysis.
Usage
chop(data, cols, ..., error_call = current_env())
unchop(
data,
cols,
...,
keep_empty = FALSE,
ptype = NULL,
error_call = current_env()
)
Arguments
- data
A data frame.
- cols
<
tidy-select
> Columns to chop or unchop.For
unchop()
, each column should be a list-column containing generalised vectors (e.g. any mix ofNULL
s, atomic vector, S3 vectors, a lists, or data frames).- ...
These dots are for future extensions and must be empty.
- error_call
The execution environment of a currently running function, e.g.
caller_env()
. The function will be mentioned in error messages as the source of the error. See thecall
argument ofabort()
for more information.- keep_empty
By default, you get one row of output for each element of the list that you are unchopping/unnesting. This means that if there's a size-0 element (like
NULL
or an empty data frame or vector), then that entire row will be dropped from the output. If you want to preserve all rows, usekeep_empty = TRUE
to replace size-0 elements with a single row of missing values.- ptype
Optionally, a named list of column name-prototype pairs to coerce
cols
to, overriding the default that will be guessed from combining the individual values. Alternatively, a single empty ptype can be supplied, which will be applied to allcols
.
Details
Generally, unchopping is more useful than chopping because it simplifies
a complex data structure, and nest()
ing is usually more appropriate
than chop()
ing since it better preserves the connections between
observations.
chop()
creates list-columns of class vctrs::list_of()
to ensure
consistent behaviour when the chopped data frame is emptied. For
instance this helps getting back the original column types after
the roundtrip chop and unchop. Because <list_of>
keeps tracks of
the type of its elements, unchop()
is able to reconstitute the
correct vector type even for empty list-columns.
Examples
# Chop ----------------------------------------------------------------------
df <- tibble(x = c(1, 1, 1, 2, 2, 3), y = 1:6, z = 6:1)
# Note that we get one row of output for each unique combination of
# non-chopped variables
df %>% chop(c(y, z))
#> # A tibble: 3 × 3
#> x y z
#> <dbl> <list<int>> <list<int>>
#> 1 1 [3] [3]
#> 2 2 [2] [2]
#> 3 3 [1] [1]
# cf nest
df %>% nest(data = c(y, z))
#> # A tibble: 3 × 2
#> x data
#> <dbl> <list>
#> 1 1 <tibble [3 × 2]>
#> 2 2 <tibble [2 × 2]>
#> 3 3 <tibble [1 × 2]>
# Unchop --------------------------------------------------------------------
df <- tibble(x = 1:4, y = list(integer(), 1L, 1:2, 1:3))
df %>% unchop(y)
#> # A tibble: 6 × 2
#> x y
#> <int> <int>
#> 1 2 1
#> 2 3 1
#> 3 3 2
#> 4 4 1
#> 5 4 2
#> 6 4 3
df %>% unchop(y, keep_empty = TRUE)
#> # A tibble: 7 × 2
#> x y
#> <int> <int>
#> 1 1 NA
#> 2 2 1
#> 3 3 1
#> 4 3 2
#> 5 4 1
#> 6 4 2
#> 7 4 3
# unchop will error if the types are not compatible:
df <- tibble(x = 1:2, y = list("1", 1:3))
try(df %>% unchop(y))
#> Error in unchop(., y) :
#> Can't combine `y[[1]]` <character> and `y[[2]]` <integer>.
# Unchopping a list-col of data frames must generate a df-col because
# unchop leaves the column names unchanged
df <- tibble(x = 1:3, y = list(NULL, tibble(x = 1), tibble(y = 1:2)))
df %>% unchop(y)
#> # A tibble: 3 × 2
#> x y$x $y
#> <int> <dbl> <int>
#> 1 2 1 NA
#> 2 3 NA 1
#> 3 3 NA 2
df %>% unchop(y, keep_empty = TRUE)
#> # A tibble: 4 × 2
#> x y$x $y
#> <int> <dbl> <int>
#> 1 1 NA NA
#> 2 2 1 NA
#> 3 3 NA 1
#> 4 3 NA 2